Question

There are four solutions to the equation: $x^4 - 12x^2 - 64 = 0$ The two real solutions are $\pm$ and the two imaginary solutions are $\pm$ i.

          There are four solutions to the equation:
$x^4 - 12x^2 - 64 = 0$
The two real solutions are $\pm$  and the two imaginary solutions are $\pm$ i.

There are four solutions to the equation:
x^4 - 12x^2 - 64 = 0
The two real solutions are ± and the two imaginary solutions are ± i.

Added by Brenda C.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

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Solved by Expert Heather Zimmers

04/14/2020

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There are four solutions to the equation: x^(4)-12x^(2)-64=0 The two real solutions are +- and the two imaginary solutions are +- i. There are four solutions to the equation: 4-122-64=0 The two real solutions are and the two imaginary solutions are