There are two boxes. Each box contains 10 balls numbered from 1 through 10. A random sample of size 6 is selected from each box. (6 balls are randomly drawn from each box, without replacement.) What is the probability that samples contain exactly 3 balls having the same numbers in common.
Added by Jorge H.
Step 1
This can be calculated using the combination formula: ${{10}\choose{6}} = \frac{10!}{6!(10-6)!} = 210$ ways in each box. Show more…
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