00:01
Hello, here a block is held in place by rope on a frictionless incline.
00:06
This block has a mass of 10 .8 kilograms and tension in the rope is 42 .6 newtons.
00:24
Here we have to determine at which angle from the incline, this tension.
00:29
Actually, we have to determine an angle of the incline.
00:33
So let's call this angle alpha.
00:35
And now let's make the sketch.
00:36
Here unfortunately no image is attached, that's why i have to basically create it myself.
00:42
Gravity is downwards and here i presume the tension is up the incline.
00:48
And normal reaction is perpendicular.
00:51
Now let's sketch this angle and we have to find this angle as it's basically how it interacts with the gravity.
00:58
As we can notice, t must be equal to mg sine alpha to keep the block in place.
01:04
And therefore this angle alpha is a sign of tension over gravity...