There is a current of 1.344 amp in a copper wire whose area of cross-section normal to the length of the wire is 1 mm2 . If the number of free electrons per cm3 is 8.4 × 1022, then the drift velocity would be
Added by Arun B.
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4 x 10\(^{22}\)), and \( V \) is the volume of the wire (1 mm\(^2\) x length of the wire). Show more…
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There is a current of 1.344 amp in a copper wire whose area of cross-section normal to the length of the wire is 1mm2. If the number of free electrons per cm3 is 8.4×1022, then the drift velocity would be
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There is a current of $1.344$ amp in a copper wire whose area of cross-section normal to the length of the wire is $1 \mathrm{~mm}^{2}$. If the number of free electrons per $\mathrm{cm}^{3}$ is $8.4 \times 10^{22}$, then the drift velocity would be (a) $1.0 \mathrm{~mm} / \mathrm{s}$ (b) $1.0 \mathrm{~m} / \mathrm{s}$ (c) $0.1 \mathrm{~mm} / \mathrm{s}$ (d) $0.01 \mathrm{~mm} / \mathrm{s}$
There is a current of 10 amperes in a copper wire of 10?7 square metre area of cross-section. If the number of free electrons per cubic metre is 1029, then the drift velocity is
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