00:01
Hello students, for part a, circuit diagram for s domain, that is this diagram and for part b, we have to find out the separate equation for mesh 1 and mesh 2 by using kirchhoff's voltage law.
00:16
First for mesh 1, using kirchhoff's voltage law, the equation will be, equation will be 42 plus 8 .4 s bracket into i1 s minus 42 i2 into s is equals to 336 divided by 5.
00:47
This is for equation 1 and kvl, kirchhoff's voltage law for mesh 2, kirchhoff's voltage law for mesh 2, the equation will be 10 s i2 plus 48 i2 plus 42 into i2 minus i1 is equals to 0.
01:14
From this, we can write down the expression as minus 42 i1 into s plus 10 s plus 90 i2 into s is equals to 0.
01:31
This is equation.
01:32
Now, for c, we are going to find out the i1, the current value by using the equation, equation 2, this equation.
01:53
From that, we can write it down, i1 into s is equals to 10 of s plus 90 divided by 42 into i s into s.
02:08
This is equation number 3.
02:12
Substitute i1 s in equation 1.
02:20
So, we get i2 s is equals to 168 divided by s into s plus 2 into s plus 12.
02:35
This is the fourth equation...