Question

Thermal decomposition of ethane gives mainly H2 + C2H4. In addition, small amounts of CH4 are formed. The decay of the C2H6 concentration can be described by the reaction steps C2H6 -> CH3 + CH3 (1) CH3 + C2H6 -> CH4 + C2H5 (2) C2H5 -> C2H4 + H (3) H + C2H6 -> C2H5 + H2 (4) H + C2H5 -> C2H6 (5) Using the steady-state approximations for the radicals [CH3],[C2H5], and [H], derive a rate law describing the overall decay of [C2H6]. From the C − H bond dissociation energies in C2H6 and C2H5, it is known that 𝑘𝑘3 ≫ 𝑘𝑘1

          Thermal decomposition of ethane gives mainly H2 + C2H4. In addition, small amounts of
CH4 are formed. The decay of the C2H6 concentration can be described by the reaction
steps
C2H6 -> CH3 + CH3 (1)
CH3 + C2H6 -> CH4 + C2H5 (2)
C2H5 -> C2H4 + H (3)
H + C2H6 -> C2H5 + H2 (4)
H + C2H5 -> C2H6 (5)
Using the steady-state approximations for the radicals [CH3],[C2H5], and [H], derive a rate law
describing the overall decay of [C2H6].
From the C − H bond dissociation energies in C2H6 and C2H5, it is known that 𝑘𝑘3 ≫ 𝑘𝑘1

Added by Lidia L.

Question

Please give Ace some feedback