00:02
Hello, so for the first part of this question, we're going to use conservation of energy, which is that the kinetic energy at the surface of the planet plus the potential energy at the surface should be equal to the kinetic energy far away or at infinity plus the potential energy at infinity.
00:32
The potential energy formula is given by u plus g, the mass of the planet, the mass of the body to be launched, the mass of the surface, and then the radius of the planet.
00:53
And there's a negative sign here because gravity is doing work.
00:59
So, at infinity, the velocity is almost zero, which means the kinetic energy almost zero.
01:09
At infinity, there is no interaction, so the potential energy is zero.
01:13
So what i'm going to have will be the kinetic energy at the surface because the negative potential at the surface.
01:24
But the potential is given by the negative of that and there's already a negative sign here.
01:31
So i'm going to be left to positive.
01:39
Mp mess.
01:44
But the radius of the planet, we also know that a width or a body on the surface of a planet it was balanced by the force of attraction between them, which is mpms all over r squared.
02:13
That's the radius of the planet squared.
02:17
I'm just going to take up one r and take it to the left.
02:21
So i'm going to be left with m.
02:26
G .r .p.
02:29
To be equal to g .m .p .ms over rp.
02:40
And from the question this will be our kinetic energy so we also say that the initial kinetic energy should be equal to that so this is what this is the first part of the question just to be proven and for the second part of the question let me check that real quick we want to calculate the temperature the escape temperature all right so let's go to the b part so for the b part, we already know from part a that the kinetic energy equals m and g rp.
04:08
So i'm talking about this one, this one right here, which is ki.
04:18
So i'm going to label this equation one.
04:25
And the full definition for kinetic energy is half, lv squared, where v would be the average speed.
04:35
So i can equate these two expressions.
04:40
So if i label this equation 2, i can equate the two expressions.
04:46
And i have half and the average squared equals ndrp.
05:02
We also know from ideal gases that the kinetic energy is given by 3 over 2 times the bottom constant times the temperature.
05:22
So i'm going to equate these two equations.
05:25
It all represent kinetic energy.
05:30
So i'm going to have 3 over 2 kt will be equal to mgrp.
05:43
I'm going to isolate the temperature.
05:47
So t will go to m.
05:52
Let me do this well.
05:54
So it's going to be 2m.
06:02
Rp all over.
06:15
So that is that.
06:16
I'll do my substitution shortly.
06:22
So i need to get the mass of nitrogen.
06:31
To get a mass of nitrogen or the mass of one nitrogen molecule, mass of one nitrogen molecule, that is going to be the molar mass divided by aguagos cancer.
06:52
That's i'm looking for the mass of a molecule.
06:55
So this is going to be the molar mass is 28 and 10 to the minus 3 kilogram.
07:03
Kilogram per mole divided by abrogandalous constant 0 .02 times 10 to 23 molecules per mole.
07:29
So the mass of the nitrogen molecules is going to be 4 .65 times 10 to the negative 26 kilogram per molecule.
08:02
Okay so now i can find my temperature.
08:05
This is 2.
08:06
This is 2...