00:01
Here in this question we have to calculate the noise power density of the generator where the resistor is given that is 50 ohm at the root temperature that is 290 kelvin.
00:11
We have to find out the available noise power where the bandwidth is given that is equals to 1 gigahertz.
00:19
So here in this question we can say that to calculate the noise density we have to calculate the noise power density which is represented by n naught that is equals to 4 k t r which is divided by b where k is the boltzmann constant the value of k is 1 .38 multiplied by the 10 raised to the power minus 23 joule per kelvin, t is the temperature and r is the resistance, b is the bandwidth.
00:49
So plug in to the value so t from here is equals to 290 of kelvin minus r that from here is equals to 50 minus b that is equals to 1 gigahertz which is equals to 1 multiplied by the 10 raised to the power 9 hertz.
01:08
So from here plug in to the value the value of n naught become equals to 4 which is multiplied by the 1 .38 multiplied by 10 raised to the power 23 which is multiplied by the 290 that is further multiplied by the 50 which is divided by 1 multiplied by the 10 raised to the power 9.
01:24
So simplifying the term we get the value of n naught that become equals to 8 .04 which is multiplied by the 10 raised to the power minus 20 weber per hertz this is the value of the n naught from here.
01:35
Now we have to calculate the value of the noise power.
01:39
So noise power which is represented by pn from the resistor of the given bandwidth is given as pn that is equals to b naught which is sorry it is n naught which is multiplied by the b.
01:52
So plug in to the value from here so we can say that this value from here will be equals to p of n that is equals to 8 .04 which is multiplied by the 10 raised to the power minus 20 multiplied by the 10 raised to the power 9...