Thermodynamics 1. An ideal gas is contained in a rigid cylinder. Determine the specific volume (m^3/kg) of the gas in the cylinder given the following information. Gas constant = 0.265 kJ/kg-K Pressure = 243.84 kPa Temperature = 410 K 2. A piston-cylinder assembly contains 1.63 kg of air at T1 = 300 K and P1 = 200 kPa. The air is brought to a final temperature of T2 = 939 K at a constant pressure. Determine the total heat transfer Q (kJ) into the assembly during the process. Ideal Gas Properties of Air T (K) Cp (kJ/kg·K) h (kJ/kg) u (kJ/kg) s (kJ/kg·K) Pr 200 1.00424 199.97 142.56 1.29559 0.3363 300 1.00371 300.26 214.15 1.70226 1.3867 400 1.01358 401.06 286.23 1.99215 3.8069 500 1.03039 503.21 359.68 2.22003 8.4205 600 1.05137 607.27 435.04 2.40970 16.304 700 1.07431 713.55 512.61 2.57348 28.846 800 1.09755 822.14 592.50 2.71846 47.799 900 1.11988 933.03 674.68 2.84903 75.330 1000 1.14053 1046.06 759.01 2.96811 114.06 1100 1.15904 1161.06 845.30 3.07770 167.08 1200 1.17526 1277.80 933.33 3.17926 238.00 1300 1.18927 1396.04 1022.87 3.27390 330.95 1400 1.20129 1515.58 1113.70 3.36249 450.59 1500 1.21168 1636.24 1205.66 3.44573 602.17 1600 1.22081 1757.88 1298.59 3.52423 791.55 1700 1.22906 1880.38 1392.38 3.59849 1025.3 1800 1.23672 2003.67 1486.97 3.66896 1310.5 1900 1.24394 2127.71 1582.30 3.73602 1655.4 2000 1.25067 2252.44 1678.33 3.80000 2068.7 2100 1.25661 2377.82 1775.00 3.86117 2560.0 2200 1.26113 2503.72 1872.19 3.91974 3139.5 2250 1.26256 2566.81 1920.93 3.94810 3465.5 Vr 1707.1 621.02 301.62 170.45 105.64 69.661 48.044 34.296 25.168 18.899 14.473 11.276 8.9190 7.1506 5.8024 4.7598 3.9427 3.2947 2.7752 2.3547 2.0116 1.8638
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To determine the specific volume of the gas in the cylinder, we need to use the ideal gas law equation: PV = mRT, where P is the pressure, V is the volume, m is the mass, R is the gas constant, and T is the temperature. Show more…
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I'm very lost, i got 3 tho!
Sheh Lit C.
A metal cylinder has a base area of A = 0.01 m² and is fitted with a piston that can freely move. The cylinder is filled with n = 0.055 mol of an ideal gas that has a pressure P = 104000 Pa, volume V = 0.0012 m³, and a temperature of T = ?. The gas is then taken through the four-step process below: State 1: The gas is in contact with an ice-water bath, keeping the gas at T₁ = 273 K. A metal block of mass m = 42 kg is placed on top of the piston, compressing the gas to State 2. State 2: The block is still on the piston, and the ice-water bath is removed. Instead, a boiling water bath is put in contact with the cylinder, raising the gas temperature to T₂ = 100 °C. State 3 + 4: The block is then removed from the piston, and the gas expands to State 4 while still in contact with the boiling water bath, keeping the gas at T₃ = 100 °C. State 4 + 1: Finally, the boiling water bath is removed and replaced by the ice-water bath, and the gas temperature is brought back down to T₄ = ?. For each process below, circle one process type: The process from State 1 to State 2: isothermal, isobaric, isovolumetric, adiabatic. The process from State 2 to State 3: isothermal, isobaric, isovolumetric, adiabatic. The process from State 3 to State 4: isothermal, isobaric, isovolumetric, adiabatic. The process from State 4 to State 1: isothermal, isobaric, isovolumetric, adiabatic.
Madhur L.
Problem 4: Consider a cylinder with a movable piston containing moles of an ideal gas. The entire apparatus is immersed in a constant temperature bath of temperature T Kelvin. The piston pushes slowly outward on an external body, which matches the force momentarily at each instant so that the gas expands quasi-statically from volume V1 to V2 at constant temperature T. The isothermal process is shown in the figure above, where the pressure p is related to the volume V by the ideal gas law as follows: pV = nRT, where R is the gas constant. Part (a) Write an expression for the work Wv done by the gas on the external body: W = nRT ln(V2/V1). Part (b) For n = 4 moles, T = 295 K, and V2 = 4.5V1, determine the work done by the gas on the external body: The gas constant is R = 8.314 J/(K mol).
Sri K.
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