This equation represents a chemical reaction at...

This equation represents a chemical reaction at equilibrium: 2SO2 (g) + O2 (g) = 2SO3 (g) What will happen when the concentration of SO3 is increased? A The reaction shifts to the right, and concentrations of SO2 (g) and O2 (g) decrease. B The reaction shifts to the left, and concentrations of SO2 (g) and O2 (g) increase. C The reaction shifts to the left, and concentrations of SO2 (g) and O2 (g) decrease. D The reaction shifts to the right, and concentrations of SO2 (g) and O2 (g) increase.

Transcript

00:02 Hi there.

00:03 In this question, we are given this equation that is in equilibrium, and we are adding more so3.

00:13 So the concentration of so3 is increased.

00:20 And we want to know what's going to happen here.

00:23 Well, to answer this question, we need leschette's principle.

00:30 Well, the chalier said, then we have a system at equilibrium.

00:33 If a stress is applied, the system will shift to relieve that stress.

00:57 All right.

00:58 So when a stress is applied to a system at equilibrium, the equilibrium will shift to relieve that stress.

01:22 Okay, so in this one, we are adding more of the product.

01:27 At equilibrium, the forward reaction and reverse reaction are constant, and the concentrations of the reactants and the concentrations of the products are constant.

01:38 They're not necessarily equal to each other.

01:40 In fact, most likely they are not, but they do remain constant because the rate of exchange is constant.

01:45 But if we increase the amount of the product, that is going to cause a stress.

01:51 Now there's more product than there should be.

01:54 So the equilibrium, in other words, the reverse reaction is going to speed up.

02:01 This is referred to as a shift in the equilibrium.

02:05 Therefore, the amount of so3 will decrease, trying to get it back to where it was.

02:12 But if more of that is becoming reactants, the concentration of each...

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