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34. The speed of a hydraulic cylinder is controlled by means of a series pressure-compensated flow control valve, as shown in the given circuit. Given: Pump: V_g = 25 cm3/rev n = 1000 rpm ?v = 0.95 ?m = 0.93 ?h = 1 Directional control valve: Q = 6 × 10?? ??P Relief valve: Cracking pressure = 6 MPa Override pressure = 0 Hydraulic cylinder: f = 2000 Ns/m v = 0.1 m/s F = 9000 N Piston diameter = 60 mm Rod diameter = 25 mm No inner leakage Calculate: P1, P2, P3, Pp, Q1, Q2 Power losses in the DCV Power losses in the FCV Pump real flow rate

          34. The speed of a hydraulic cylinder is controlled by means of a series pressure-compensated flow control valve, as shown in the given circuit.
Given:
Pump:
V_g = 25 cm3/rev
n = 1000 rpm
?v = 0.95
?m = 0.93
?h = 1
Directional control valve:
Q = 6 &times; 10?? ??P
Relief valve:
Cracking pressure = 6 MPa
Override pressure = 0
Hydraulic cylinder:
f = 2000 Ns/m
v = 0.1 m/s
F = 9000 N
Piston diameter = 60 mm
Rod diameter = 25 mm
No inner leakage
Calculate:
P1, P2, P3, Pp, Q1, Q2
Power losses in the DCV
Power losses in the FCV
Pump real flow rate

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34. The speed of a hydraulic cylinder is controlled by means of a series pressure-compensated flow control valve, as shown in the given circuit.
Given:
Pump:
Vg = 25 cm3/rev
n = 1000 rpm
?v = 0.95
?m = 0.93
?h = 1
Directional control valve:
Q = 6 times; 10?? ??P
Relief valve:
Cracking pressure = 6 MPa
Override pressure = 0
Hydraulic cylinder:
f = 2000 Ns/m
v = 0.1 m/s
F = 9000 N
Piston diameter = 60 mm
Rod diameter = 25 mm
No inner leakage
Calculate:
P1, P2, P3, Pp, Q1, Q2
Power losses in the DCV
Power losses in the FCV
Pump real flow rate

Added by Alex J.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Supreeta N

10/09/2023

Step 1

Power losses in the DCV: To calculate the power losses in the directional control valve (DCV), we need to consider the pressure drop across the valve and the flow rate passing through it. The pressure drop across the valve can be calculated using the formula: ΔP Show more…

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34. The speed of a hydraulic cylinder is controlled by means of a series pressure-compensated flow control valve, as shown in the given circuit. Given: Pump: V = 25 cm/rev, n = 1000 rpm, Η = 0.95, Ηv = 0.93, Ηm = 1 PQ Directional control valve: Q = 610 - P Relief valve: Cracking pressure = 6 MPa, Override pressure = 0 Hydraulic cylinder: f = 2000 Ns/m, v = 0.1 m/s, F = 9000 N, Piston diameter = 60 mm, Rod diameter = 25 mm, No inner leakage Calculate: 1. Power losses in the DCV 2. Power losses in the FCV 3. Pump real flow rate

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