0:00
Hello.
00:02
In this problem, we have an atwood machine, which is basically a bully and a cord with two masses hanging on each side.
00:14
So here we have a mass of 7 kilograms, and on the other side we have another mass of 9 kilograms.
00:22
The question here is to determine the acceleration of this group here and also to find the tension in the cord.
00:32
So let's first draw the forces on each object here.
00:37
So here we have the weight of this 9 kilograms object.
00:41
F weight is equal to the mass of the object multiplied by the gravitational acceleration.
00:49
This looks like g, so let's remove this part here.
00:54
So that's the first force.
00:57
The second force here is the force of weight also of the other block, and it's equal to 7 multiplied by 9 .81.
01:09
Here, ignoring the friction of this bully here makes the tension equal on each side.
01:15
So we have a force of tension here acting on this 7 kilograms block and another force of tension which is equal to this one also acting on this 9 kilograms block.
01:29
From here, let's get the equation of motion of each one of them or simply applying no second law to each block individually.
01:39
So let's start by the nine kilograms block.
01:42
We know that the sum of forces on that block will be equal to the mass times the acceleration of that block.
01:51
So here, we assume that the direction of motion will be favored to the nine kilograms.
02:01
So this one is going down.
02:03
So let's assume that down is positive.
02:05
And upward is negative here...