0:00
Hello.
00:01
So in this question, it is given that is the concentration of this hno3, that is nitric acid, it is 16m.
00:12
And the volume taken here is 3m or we can write it as 0 .003 liter.
00:21
So now the moles of the hno3, we know that, that is the moles is equal to molarity into volume.
00:33
So therefore, molarity here that is 16 multiplied by the 0 .003, which is equal to 0 .048 moles.
00:45
So this is the moles of the nitric acid.
00:50
Now the given here, that is the copper wire is 0 .380 gram.
01:01
So now the moles of copper is equal to, again we know that the moles is equal to the mass divided by the molar mass and which is equal to 0 .380 divided by the molar mass of the copper is 63 .546 and this will become 0 .00598.
01:28
This is the mole.
01:29
Now the reaction here that is copper plus 4 hno3 it will form co copper nitrate cono3 twice plus 2no2 plus 2h2o so here as per the stuometry of the reaction we can say that one mole of copper it is reacting with the 4 mole of hno3...