Three cables are attached to the top of the tower at A. Determine the smallest angle formed by cables AD and AB if the height of the tower is $a = 52 m$. The smallest angle formed by cables AD and AB is $\boxed{}$ °.
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Let D be the point ( -14, 0, 0). Let B be the point (16+16, 0, 12) = (32, 0, 12). The vector $\vec{AD}$ is given by $\vec{AD} = D - A = (-14, -52, 0)$. The vector $\vec{AB}$ is given by $\vec{AB} = B - A = (32, -52, 12)$. Show more…
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