Three capacitors are joined as depicted in the figure, C1 = 6.8 μF, C2 = 12.2 μF, C3 = 3.8 μF. The battery has a voltage of 12 V. Calculate the numerical value of the total energy stored in the capacitors U, in microjoules.
Added by Erik M.
Step 1
In a series circuit, the equivalent capacitance is given by: 1/Ceq = 1/C1 + 1/C2 + 1/C3 Substituting the given values: 1/Ceq = 1/6.8 + 1/12.2 + 1/3.8 Calculating the sum: 1/Ceq = 0.147 + 0.082 + 0.263 1/Ceq = 0.492 Ceq = 1/0.492 Ceq = 2.03 μF Now, we can Show more…
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