00:01
Okay then i've dealt three cards one at the time no replacement i want to find the chance for getting an ace on the third card well let's look at what could happen it could be ace first ace second ace third one way of doing it and to get that four aces on 52 and three aces from 51 two aces from 50 that will be four times three is 12, 24 on top over 52 times 51 times 50.
00:45
1, 3, 600.
00:52
Then it could be this, it could be ace first, then no ace, then ace.
00:59
The chance of that happening is 452.
01:04
No ace, there's 48 cards under aces, 51, and then three aces left.
01:12
Of 50.
01:14
So here we have 12 times 48 and the top together.
01:19
This is 5 -76 over 1, 3, 2, 600.
01:27
Then it could be no ace first, followed by ace, followed by ace.
01:33
And that chance of happening is 48 out of 52 times 4 out of 51, times 3 out of 50.
01:46
The same thing as the 1b4, in in fact, on three, two, 600, and on top, five, seven, six.
01:57
The last thing of getting it would be no ace, no ace, followed by ace.
02:03
And that chance will be 48, 52, 47, 51, and then four out of 50, four aces left in the pack.
02:15
So 48 times 47 times four is 9 .024.
02:24
Again, same number on the bottom.
02:28
So last step then, there are four ways then to get ace as a third card with aces before or not before.
02:37
So add up those numbers.
02:40
Let's add up 24 plus 576 plus 576 plus 976 plus 9024...