Three charges are at the corners of an isosceles triangle as shown in the figure (Figure 1) . The ±5.00μC charges form a dipole.
I already figured out that the force the -10.00μC exerts on the dipole is F= 1680 N; the torque exerted on the dipole by the -10.00μC τ= 22.3 m clockwise. But I can't figure out the direction of the force the -10.00μC exerts on the dipole (counterclockwise from the +y- direction)
Please show work, thank you.