Question

Three charges are fixed along a line. Q1 has a charge of +10nC, Q2 has a charge of -4nC, Q 3 is a proton. The distance between Q1 and Q2 is 3mm and the distance between Q2 and Q3 is 12mm. (1) Calculate the force acting on the proton (magnitude and direction) (2)Calculate the electric potential at the position of the proton

          Three charges are fixed along a line.
Q1 has a charge of +10nC, Q2 has a charge of -4nC, Q 3 is a proton.
The distance between Q1 and Q2 is 3mm and the distance between Q2 and Q3 is 12mm.
(1) Calculate the force acting on the proton (magnitude and direction)
(2)Calculate the electric potential at the position of the proton
        
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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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Three charges are fixed along a line. Q1 has a charge of +10nC, Q2 has a charge of -4nC, Q 3 is a proton. The distance between Q1 and Q2 is 3mm and the distance between Q2 and Q3 is 12mm. (1) Calculate the force acting on the proton (magnitude and direction) (2)Calculate the electric potential at the position of the proton
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Transcript

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00:01 Let's discuss this question.
00:02 So here 2 .4s are given to us which is separated by radius r that is 3 cm.
00:08 So we need to find the magnitude and direction of the electric force a that is that q1 exerts on q2 and secondly q2 that exerts on q1.
00:18 Q1 is equal to plus 25 nanopulm and here q2 is equal to minus 75 nanopulm.
00:26 R is equal to 3 .0 centimeter.
00:29 So for example this is force that is f1 2 and this is the force that is f21 that is 2 exerted on 1 and this was force 1 1 exerted on 2 this is plus 25 nanofulm and this is minus 75 nanopulm q1 and q2 so here we can say a that is the force exerted by 1 on 2 so here the formula will be f e that is equal to k multiplied by q1 q 2 divided by r square so here f e will be equal to 9 multiplied by 10 raised to 9 newton meters square divided by fulam square multiplied by 25 multiplied by 75 multiplied by 10 x squared and divided by 3 multiplied by 3 multiplied by 10 to minus 4 so this is equal to 9 multiplied by 25 multiplied by 75 multiplied by 10 minus 5 divided by 9.
01:33 So here we can say canceling this 9.
01:38 So here force that is f1 2 will be equal to 1 .8 .75 multiplied by 10 raise to minus 3 newton...
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