$vec{F_1}$ (5N) $vec{F_2}$ (4N) $37^circ$ $53^circ$ $vec{F_3}$ (5N) $x$ $y$
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First, we need to find the components of the given forces along the x and y directions. Force 1 (F1): 8 N at 30° F1x = 8 * cos(30°) = 8 * (√3/2) = 4√3 N F1y = 8 * sin(30°) = 8 * (1/2) = 4 N Force 2 (F2): 5 N at 60° F2x = 5 * cos(60°) = 5 * (1/2) = 2.5 N F2y = 5 Show more…
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