Question

Three long, straight wires are seen end-on in the figure below. The distance between the wires is $r = 0.266$ m. Wires A and B carry current $I_A = I_B = 1.75$ A, and wire C carries current $I_C = 3.30$ A. Assume (for example) the only forces exerted on wire A are due to wires B and C. Find the force per unit length exerted on the following. (Express your answers in vector form.) (a) wire A $\vec{f}_A = (0.000027\hat{i} + 0.0000752\hat{j})$ N/m (b) wire B $\vec{f}_B = (0.0000549\hat{i} + 0.0000199\hat{j})$ N/m

          Three long, straight wires are seen end-on in the figure below. The distance between the wires is $r = 0.266$ m. Wires A and B carry current $I_A = I_B = 1.75$ A, and wire C carries current $I_C = 3.30$ A. Assume (for example) the only forces exerted on wire A are due to wires B and C. Find the force per unit length exerted on the following. (Express your answers in vector form.)
(a) wire A
$\vec{f}_A = (0.000027\hat{i} + 0.0000752\hat{j})$ N/m
(b) wire B
$\vec{f}_B = (0.0000549\hat{i} + 0.0000199\hat{j})$ N/m

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three long straight wires are seen end on in the figure below the distance between the wires is r 0266 m wires a and b carry current ia ib 175 a and wire c carries current ic 330 a assume 02033

Added by Luke A.

University Physics with Modern Physics

Hugh D. Young 14th Edition

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Solved by Expert Umang S

03/05/2022

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We are given the distance between the wires, $r = 0.266$ m, and the currents in each wire: $I_A = I_B = 1.75$ A, and $I_C = 3.30$ A. The wires are arranged in an equilateral triangle. The force per unit length between two parallel wires carrying currents $I_1$ Show more…

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Three long, straight wires are seen end-on in the figure below. The distance between the wires is $r = 0.266$ m. Wires A and B carry current $I_A = I_B = 1.75$ A, and wire C carries current $I_C = 3.30$ A. Assume (for example) the only forces exerted on wire A are due to wires B and C. Find the force per unit length exerted on the following. (Express your answers in vector form.) (a) wire A $\vec{f}_A = (0.000027\hat{i} + 0.0000752\hat{j})$ N/m (b) wire B $\vec{f}_B = (0.0000549\hat{i} + 0.0000199\hat{j})$ N/m

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