00:01
So for this problem, we are looking for the probability that marksman 3 missed.
00:07
So i'll say m, that is the event m3 complement.
00:12
So that is if we had the event m3, then marksman 3 hit, m3 complement, he missed, or they missed, rather.
00:20
Given that two of the marksman hit, the way that we would find this is by finding the probability that marksman 3 misses, and inherently that must mean if two hit, that means that marksman 2 and marksman 1 both hit, divide that by the probability of only two of the three hitting.
00:48
So we know that looking at the different probabilities, we have the probability of marksman 3 missing would be 1 minus 0 .9, so that should be 0 .1.
00:59
Probability of marksman 1 hitting would be 0 .25, and probability of marksman 2 hitting be 0 .4.
01:09
We then divide that by, well, for finding the probability that 2 of them hit, there are three different ways for that to occur...