00:01
So we are given that heat input to the system is 2531 jules and work into the system is 790 joules.
00:09
We are given that the number of moles is 3 and the gas is monoatomic.
00:14
Mono atomic.
00:16
So cv would be 1 .5r that is 1 .5 times 8 .314.
00:22
We all know that as per the first law of thermodynamics, law of thermodynamics.
00:36
That net change in internal energy is equal to q plus w.
00:43
So that means change in internal energy here would be would be heat input which is 2 531 plus work input that is 790.
00:54
As per the formula, we all know that c delta v, sorry, delta u, that is changing in internal energy is number of moles time cv times delta t.
01:03
So from here we can say that change in temperature delta t would be 2 .5.
01:07
531 plus 790 divided by 3 times 1 .5 of r which is 8 .314.
01:17
So this is the change in temperature...