00:01
In this question, they have given that three charges are placed on a line and we have to calculate the net gravitational force on the charge b and this charge b is far 72 cm from both the charges.
00:14
Now, how can we calculate this? first of all, we have charge on b that is 45, multiply by 10 -to -the -power minus 6 coulum.
00:22
So let's say if i calculate the charge due to b and c, it will be equal to k.
00:30
Qb multiplied by qc divided by rbc square.
00:35
Now if i put the values, k will be 9, multiply by 10 rich to the power 9, multiply by the charge on b, that is 45, multiply by 10 to the power minus 6, multiply by charge on c, that will be equal to minus 83, multiply by 10 rich to the power minus 6 again.
00:58
And we will divide this by the radius between b c that is 72 centimeter or i can say 72 multiply by 10 raise to the power minus two meter and we will whole square of this now we will not assume the negative charge on this charge because it is just showing the direction of the charge that it is attractive or repulsive in nature so if i found my f bc it will be approximately equal to 6 .4 .8 newton...