00:01
Hello student, three people toss a coin and the old man pays for a coffee.
00:06
If the coins all turn up the same, they tossed again.
00:10
And we have to find the probability that the fewer than the three tosses are needed and the type of the variable distribution is needed.
00:19
Then here are the two ways to do this.
00:23
The first way is either two people get head and one get tail.
00:40
Or the second way is that the two people get tail and one get head.
00:54
If they are all getting the same, then we have to repeat the process.
00:58
Then this is the only two possibilities.
01:00
Then the probability of each of these are as follows.
01:22
The probability of getting the head or the tail is 1 by 2 because there are only two possibilities if we are getting the head or we are getting the tail.
01:32
Then for getting the head, the probability is 1 by 2 or for getting the tail, the probability is again 1 by 2.
01:39
Then two heads are there.
01:40
The 1 by 2 raise to 2 and the one tail is there.
01:43
Then it's simply 1 by 8.
01:47
Next, the probability of getting the two tails and one head.
01:54
In a similar way, we can calculate two tails means 1 by 2 raise to 2 into one head means 1 by 2.
02:00
We get the same probability 1 by 8.
02:03
Now probability having an odd man in the single toss.
02:10
Then in this only two cases, the odd man pays a single toss.
02:15
Then which is a 1 by 8 into sorry not a into it's a plus 1 by 8.
02:23
Then 1 by 8 by 1 by 8 is 2 by 8 and it's simply 1 by.
02:28
Then by using this probability, we can say that the odd man pays the 1 by 4 means 0 .25...