Three photons strike a metal surface. Photon 3 has twice the energy of photon 2, which has twice the energy of photon 1. Photon 1 has just enough energy to eject an electron from the metal with no kinetic energy. How much faster is the electron ejected by photon 3 moving as compared to photon 2? 4 times 1.73 times 1.41 times 2 times they are moving at the same speed
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This energy is known as the work function of the metal. Photon 2 has twice the energy of photon 1. This means it has enough energy to overcome the work function and still have some energy left to give the electron kinetic energy. Photon 3 has twice the energy Show more…
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A photon of energy $E$ interacts with an electron at rest and undergoes pair production, producing a positive electron (positron) and an electron (in addition to the original electron): $$ \text { photon }+\mathrm{e}^{-} \rightarrow \mathrm{e}^{+}+\mathrm{e}^{-}+\mathrm{e}^{-} $$ The two electrons and the positron move off with identical momenta in the direction of the initial photon. Find the kinetic energy of the three final particles and find the energy $E$ of the photon. (Hint: Conserve momentum and total relativistic energy.)
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