00:01
Hi, here this given problem is based upon snail's law, snail's law, which is used for refraction.
00:08
In the first case, there is sheet 1 is above sheet 2.
00:19
This is the sheet 1, this is the sheet 2, then for the laser light which is refracting from first sheet to the second sheet.
00:36
The ray is going away from the normal this is n1 index of refraction of sheet 1 this is n 2 index of refraction of sheet 2 angle of incidence over here that is 26 .5 degree angle of refraction in sheet 2 that is 31 .7 degree so using snail's law for 8 n2 by a n1, index of refraction of sheet 2 with respect to that of sheet 1, that will be given by sign of angle of incidence, sine 26 .5 degree divided by sign of angle of refraction, 31 .7 degree.
01:31
Then in the second case, this time sheet 3 is above sheet 2.
01:38
So this is sheet 2 again as the second medium but first medium is sheet 3 and for the refraction of the same laser again at the same angle of incidence again the ray of light is going away from the normal this is n3 this is n2 angle of incidence 26 .5 degree angle of refraction 3 36 .7 degree.
02:11
So n of 2 with respect to n of 3.
02:17
Again using snell's law, sign of angle of incidence, sine 26 .5 degree divided by sine 36 .7 degree.
02:34
So make it equation number 1, make it equation number 2.
02:40
Now in the third case, this time sheet 1 is above sheet 3...