0:00
Hello everyone.
00:01
Let's proceed to solve this question.
00:02
So we have three charges q1 that's equal to three microculum.
00:09
Q2 is given as to be negative of so q2 is given as 5 negative of 5 microculum and q3 is given us to be negative of all right so q3 is negative of 8 microculems.
00:28
All right.
00:29
Now they are placed at.
00:31
X -axis so this is our x -axis here and this is the origin here so in the origin q1 is placed in the origin so three microculum charges here and q2 is placed at a distance of 0 .2 meters so q2 is placed here so negative of 5 microculum so where will q3 be placed such that the net force so the net force on q1 will be seven all that's sorry so the net force on q1 is seven microculems sorry seven newtons all right so as this is a positively charged quantity positively charged and this is a negatively charged quantity so there will be a force of attraction between them so q2 will pull this towards itself so this force will be in this direction all right so q3 cannot be placed here cannot be placed here all right so q3 must be placed somewhere here q3 will be somewhere here such that the two forces like the negative of two forces gives seven newtons all right so let's say the force which q2 applies on q1 is f1 and the force which q3 applies on q1 is f13.
02:19
All right.
02:20
So we can write an equation.
02:23
The net force will simply be equal to f13 minus f112 as these two forces are in opposite directions.
02:35
So let's substitute the values.
02:37
F net is 7 and the force of attraction or repulsion between two charges is given as k, q1, q2 divided by the square of distance between them.
02:50
And the distance between q1 and q3 is to be found.
02:55
All right.
02:55
So let us assume this to be r.
02:58
So the force and k here is a constant whose value is 9 multiplied by 10 to the power 9...