00:02
Hello everyone.
00:03
So in this question it is given the three point charges are arranged as shown in the figure.
00:09
So this is a rough drawing which we have drawn rough figure for the given figure in the question and the information.
00:19
So the three point charges are q1, q2 and q3 respectively.
00:27
Again it is given.
00:28
We have to find the magnitude and the direction of the electric force on the particle q which is 4 .88 newton column that is at origin.
00:43
Now first we'll find f1 which is the net force between charge q1 and q2 right so this will be equals to q1 q2 divided by 4 pi epsilon not r12 square so this is equals to q1 is equal to 4 .88 newton column that is 4 .88 multiplied by 10 raised to the power minus 9, multiplied by q2, which is equal to 6, multiplied by 10 raised to the power minus 9, 1 divided by 4 pi, epsilon 0 value becomes 9, multiplied by 10 10 raised to the power 9, 4 divided by r12 square, r12 is given the question to be 0 .235, the square of this.
01:55
So on solving this we get f1 is equal.
02:03
4771 .752 multiplied by 10 raised to the power minus 9 newton.
02:06
Similarly, we can find the value of f2, which will be equal to q1, q3.
02:13
Let us write it also...