Three point charges are fixed in a cartesian coordinate...

Three point charges are fixed in a Cartesian coordinate system as follows: q1 = 878 nC is at (8.89, 3.56) cm, q2 = -296 nC is at (-8.57, 7.83) cm, and q3 = 565 nC is at (-6.18, -3.69) cm. a) Calculate the voltage at the origin of the coordinate system due to q1 only (in kV).b) Calculate the voltage at the origin of the coordinate system due to q2 only (in kV).c) Calculate the voltage at the origin of the coordinate system due to q3 only (in kV).d) Calculate the total voltage at the origin of the coordinate system due to all three charges (in kV).e) A fourth charge Q = 57.7 C of mass 132 mg has a speed of 637 m/s when it is at the origin of the coordinate system. Calculate its total mechanical energy at that moment (in J).f) Calculate the speed of the fourth charge when it is very far away from the other three charges (in m/s).

Transcript

00:01 Hi guys now in this volume the diagram is looking like this we have a q and q2 and q3 let me say that this is q1 that i have if i'm drawing a diagram this is what this is q1 that i have this is q2 and this is q3 and there is a point another which is what q4 this is q4 this is q1 i'm gonna say this is q2 and this is q3 now the coordinate of this one is given to us this is 0 comma 4 and this is 0 comma minus 4 this one is what 3 4 this is key 1 which is what q1 is equal to this is 19 nanoculum this q2 is equal to this 1 minus 19 nanoculum this q3 is equal to this one about 45 nanoculum and this q4 is equal to this will be what 180 nanoclomb the question that we are asked as what is the potential of this configuration we have four charges here we need to find that potential now potential sorry potential energy so potential we are taking a group first in this one then we have a this one then we have a this is again this one okay and then we have a only we need to find out what only these three charges not we don't need to include this four charge sorry for that one we don't need to include this 4 this q 4 we only need to include these three charges so i'm going to say that the potential energy between these two charges potential is between three charges and potentially between these charges so i would say that this potential energy the part first u is equal to i would say this is u of 1 2 and this is u of 2 3 and this is u of this is what 3 1 okay so we have u is equal to i would say that if i'm saying that this is point a and this is point b and this one is at point c and this one is at point o so this is k k1 q2 divide by the distance which is what a oa i would say plus 2 3 which means that k q2 q3 divide by this distance which is what ob plus this u3 3 1 which is what i can say k q1 q3 divide by distance but ab.

02:47 From there i would say that this u is equal to if i'm substituting all this value.

02:53 Now one thing we need to keep in mind i need to substitute charges with sign.

02:59 So if i substitute charges with a sign and i can take common word k and also i can take common these distances only this distance is oa and o b because ab is but ab will be 8...

Question

Please give Ace some feedback