Three point charges of the same magnitude q have coordinates...

"Three point charges of the same magnitude q, have coordinates equal to (0, 0) m; (+a; 0) m; and (+a, +a) respectively: In other words, they are placed at the three corners ofa right-angle triangle in the first quadrant: The charge at (0, 0) is negative; and two other 'charges are positive 50 points) Find the electric field, at the center of the triangle' s hypotenuse P. (16 pts)"

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00:01 Hi, here in this given problem, three charged particles are kept in this cartesian plane.

00:11 The first one minus q that has been kept at the origin o minus q this is.

00:22 Another plus q that has been kept at the coordinate plus a comma 0 and that is plus q.

00:32 And the third one, it has been kept at a point plus a comma plus a and that is also plus q.

00:45 Suppose this is point o, so here it may be assumed to be a and this point may be assumed to be b.

00:53 So it becomes a right angled triangle.

00:58 And we have to find net electric field at a point.

01:02 A point at the mid -point of the hypotenuse.

01:05 This is point p.

01:08 So in this right angle triangle, this distance is a and that is also a.

01:16 So it becomes an isosceles right angle triangle.

01:21 So the hypotenuse of this right angle triangle, o b, that will be equal to using pythagoras theorem, the square root of a square plus a square means that that is a root 2.

01:35 So the distance of this point p from o and b will be o p is equal to b p means that is a root 2 by 2.

01:47 And as this triangle opa that will also serve as an isosilis triangle triangle.

01:56 So that distance ap, it will also be equal to a root 2.

02:02 By 2.

02:03 Now at point p there are three electric fields...

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