00:01
Okay, so in this problem we have two identical and uncharged spheres connected by a charge wire.
00:10
So let's put the wire in a different color.
00:14
So the wire has charged and these spheres are uncharged, but they are conducting spheres, which means that when we put a conducting system in contact with a charge system, they're going to move towards an equilibrium.
00:38
Therefore we can say that the charge q and this wire is going to be divided to both particles, both spheres, sorry.
00:51
So we have the first sphere here.
00:52
The second sphere here and we have the charge the uncharged now the uncharged wire and the charge q it is now kill divided by 2 in here and q divided by 2 in the second sphere okay knowing this we know that since these spheres are had since the spheres have the same charge they go into produce what can we say? it's going to produce a force in one another.
01:31
Therefore we have a repel force acting at the center of the of one of these spheres.
01:39
And that's the tension, the force that we have to calculate in this problem.
01:44
Therefore, let's do this.
01:46
So since these two spheres are interacting with the electromagnetic, the electric force, we know that that the column force between them, between both of them is going to be equal k, q1, q2 divided by the distance that we're going to call d square.
02:13
Okay, so what is the charge in the particle, the first sphere, and what is the charge in the second sphere? well, we already said that is q divided by two.
02:24
Therefore, this is just k divided by 4 q square and what is the distance between the application point of the force well we have here one radius r we have the length l of the wire and we have the other radius of the application which is r therefore this is 2r plus l is square...