Question

1. Three vibration data sets have been posted on the course website, which were collected by using the following experimental setup. The tested bearings have three health conditions: healthy, faulty with an outer race defect, and faulty with an inner race defect. The testing conditions are: shaft rotating speed is 1200 rpm, and the sampling frequency is 32,700 Hz (selected by the monitoring system). NC: normal (healthy condition); OR: out race damage; IR: inner race damage. (a) Compute the theoretical characteristic frequencies on the amplitude spectra, corresponding to these three bearing health conditions. (b) Do fault diagnosis for these three bearings. Motor Testec bearing Gearbox Ch #1 Ch #2 Ch #3 (1) Drive motor: 3 HP. (2) Tested bearing parameters: deep-groove ball bearing, d = 7.937mm, D = 33.503mm, a = 0, Z = 8

          1. Three vibration data sets have been posted on the course website, which were
collected by using the following experimental setup. The tested bearings have three
health conditions: healthy, faulty with an outer race defect, and faulty with an inner
race defect. The testing conditions are: shaft rotating speed is 1200 rpm, and the
sampling frequency is 32,700 Hz (selected by the monitoring system). NC: normal
(healthy condition); OR: out race damage; IR: inner race damage.
(a) Compute the theoretical characteristic frequencies on the amplitude spectra,
corresponding to these three bearing health conditions.
(b) Do fault diagnosis for these three bearings.
Motor
Testec
bearing
Gearbox
Ch #1
Ch #2
Ch #3
(1) Drive motor: 3 HP.
(2) Tested bearing parameters: deep-groove ball bearing,
d = 7.937mm, D = 33.503mm, a = 0, Z = 8

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1. Three vibration data sets have been posted on the course website, which were
collected by using the following experimental setup. The tested bearings have three
health conditions: healthy, faulty with an outer race defect, and faulty with an inner
race defect. The testing conditions are: shaft rotating speed is 1200 rpm, and the
sampling frequency is 32,700 Hz (selected by the monitoring system). NC: normal
(healthy condition); OR: out race damage; IR: inner race damage.
(a) Compute the theoretical characteristic frequencies on the amplitude spectra,
corresponding to these three bearing health conditions.
(b) Do fault diagnosis for these three bearings.
Motor
Testec
bearing
Gearbox
Ch #1
Ch #2
Ch #3
(1) Drive motor: 3 HP.
(2) Tested bearing parameters: deep-groove ball bearing,
d = 7.937mm, D = 33.503mm, a = 0, Z = 8

Added by Lidia R.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Sri K

12/12/2022

Step 1

The theoretical characteristic frequencies for a deep-groove ball bearing can be calculated using the following formulas: Show more…

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Three vibration data sets have been posted on the course website, which were collected by using the following experimental setup. The tested bearings have three health conditions: healthy, faulty with an outer race defect, and faulty with an inner race defect. The testing conditions are: shaft rotating speed is 1200 rpm, and the sampling frequency is 32,700 Hz (selected by the monitoring system). NC: normal (healthy condition); OR: outer race damage; IR: inner race damage. (a) Compute the theoretical characteristic frequencies on the amplitude spectra corresponding to these three bearing health conditions. (b) Do fault diagnosis for these three bearings. Tested bearing Motor Gearbox Ch #1 Ch #2 Ch #3 1) Drive motor: 3 HP 2) Tested bearing parameters: deep-groove ball bearing, d=7.937mm, D=33.503mm, α=0, Z=8

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Transcript

00:01 Hello students, today we will discuss about this question.

00:05 In this question, we are given that the four shapes appear in each test cam, and the test cam are run at a fixed field and the displacement of the stylus reading on the cam is recorded.

00:25 The signals is then broken into the four signals corresponding to the four different can shapes.

00:32 Sector and each signal is broken into the frequency components and then rms of the spectrum over a selected set of frequency is compounded and these values which measures the amount cam vibration at those frequency is response variable and the data are displayed in the table so here it is cam 1 cam 2 and cam 3.

01:06 Here shape 1, shape 2, shape 3 and shape 4.

01:10 So here it is 72, 60, 40 and 54.

01:14 Now for cam 2 it will be 70, 55, 42 and 52 and for cam 3 it will be 70, 71, 56 and 59.

01:25 So here first of all we need to find, do the test, reject the null hypothesis of equal mean.

01:33 So here we need to determine whether the null hypothesis at 0 of equal mean vibration is rejected or not, yes or no.

01:58 So here, first of all, from the excel data data analysis here, two -way anova without replication, that will be here, here we can write here mu that is equals to 58 .4167 here t1 that is equals to 70 .667 t2 that is equals to 62 t3 that is equals to 46 and t4 that is equals to 55 here b1 is equals to 56 .5 b2 is equals to 54 .75 and b3 that is equals to 64 .75 so here the anova table will be here it is source of variation here df s s ms f and p value and so here shapes cars errors and total so here degree of a freedom will be 3 to 6 and total is 11 ss will be 986 .25, 193 .1667, and 121 .50...

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