Three wires meet at a junction. Wire 1 has a current of $0.40 \mathrm{A}$ into the junction. The current of wire 2 is 0.65 A out of the junction. (a) How many electrons per second move past a point in wire $3 ?$ (b) In which direction do the electrons move-into or out of the junction?
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Step 1
40 \, \text{A}\) and \(i_2 = -0.65 \, \text{A}\) (since it's out of the junction), we have: \(0.40 + (-0.65) + i_3 = 0\) \(i_3 = 0.25 \, \text{A}\) Show more…
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