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Thus, F1 can be determined by rearranging the above equation and then following the usual tactics of vector addition using components. The total amount of hanging mass and direction (with respect to the positive x axis) for the vectors F2 and F3 are given below. For vector F3: hanging mass = 816.3 grams angle = 155.0 degrees For vector F2: hanging mass = 510.2 grams angle = 235.0 degrees (a) Determine the components, the magnitude and the angle (counter-clockwise with respect to the positive x axis) of F1. x component = Newtons y component = Newtons magnitude = 10.1 Newtons angle = degrees (b) From the magnitude of F1, determine the mass of the unknown. unknown mass = grams (c) If the established value for the hanging mass used to create F1 is 921.2 grams, determine the absolute percent difference between it and the experimental value determined by the students in the lab. percent difference = %

          Thus, F1 can be determined by rearranging the above equation and then following the usual tactics of vector addition using components. The total amount of hanging mass and direction (with respect to the positive x axis) for the vectors F2 and F3 are given below.
For vector F3: hanging mass = 816.3 grams angle = 155.0 degrees
For vector F2: hanging mass = 510.2 grams angle = 235.0 degrees
 (a) Determine the components, the magnitude and the angle (counter-clockwise with respect to the positive x axis) of F1.
x component = Newtons
y component = Newtons
magnitude = 10.1 
Newtons angle = degrees
(b) From the magnitude of F1, determine the mass of the unknown. unknown mass = grams
(c) If the established value for the hanging mass used to create F1 is 921.2 grams, determine the absolute percent difference between it and the experimental value determined by the students in the lab. percent difference = %
        
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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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Thus, F1 can be determined by rearranging the above equation and then following the usual tactics of vector addition using components. The total amount of hanging mass and direction (with respect to the positive x axis) for the vectors F2 and F3 are given below. For vector F3: hanging mass = 816.3 grams angle = 155.0 degrees For vector F2: hanging mass = 510.2 grams angle = 235.0 degrees (a) Determine the components, the magnitude and the angle (counter-clockwise with respect to the positive x axis) of F1. x component = Newtons y component = Newtons magnitude = 10.1 Newtons angle = degrees (b) From the magnitude of F1, determine the mass of the unknown. unknown mass = grams (c) If the established value for the hanging mass used to create F1 is 921.2 grams, determine the absolute percent difference between it and the experimental value determined by the students in the lab. percent difference = %
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Transcript

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0:00 Hello everyone.
00:02 So from the question we know the value of f1.
00:05 Okay.
00:06 In another way we can write it as f1 with the direction is equal to 0 .98.
00:13 I in the direction of i cap.
00:17 N.
00:18 N will be capital as it is newton, right? see, this is f1 in this direction.
00:27 So it is basically i.
00:30 Okay, now see.
00:31 F1.
00:31 Will be equal to f2 that is 1 .96 newton okay at 60 degrees at 60 degrees so you can see it here right see this is f y and here it will be f2 this is at 60 degrees now see by resolving this we get the value that is f2 cost 60 that is 1 .96 multiplied by 0 .5 so the final value we get is equal to 0 .98 newton right so f2 finally gets the value that is 0 .98 i cap plus 1 .6 697 j cap in newton.
01:41 Now see, f eq, that is force balancing f1 is less than f2...
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