00:01
Hi, so with this question we're dealing with the titration of 25 milliliters 0 .1 molar concentration of hydrochloric acid, that is a strong acid, that is going to be titrated with a strong base with the same concentration, the strong base employed is sodium hydroxide.
00:25
And we want to calculate the ph after adding 15 milliliters of base.
00:36
So the first thing that we need to do is calculate the total volume that we're going to get at that that total volume is going to be 25 milliliters that i had initially from my solution plus 15 milliliters that i had from the addition.
00:52
So this is going to be 40 milliliters or 4 times 10 to the minus 2 liters.
01:00
Next thing that we need is the amount of mole of h3o plus that we're going to have in solution at the beginning, that is going to be remembering that molarity is equal to amount of mole divided by volume.
01:15
Amount of mole will be molarity times the volume.
01:19
So the initial volume for my solution of hydrochloric acid, remember this is a strong acid so it dissociates completely, and it's going to be 25 milliliters transformed to liters.
01:32
I simply need to multiply by times 10 to the minus 3, multiplied by the concentration that i'll get.
01:41
I can do the same thing for the oh minus that i'm going to add, in this case the quality changes a little bit, i added 15 milliliters instead of 25, and the concentration is the same.
01:55
So the results are 2 .5 times 10 to the minus 3 and 1 .5 times 10 to the minus 3 mole respectively...