00:01
So, let's start with the concept which we are going to use here for this question.
00:08
So, here we are going to use the enthalpy method to calculate the work input.
00:14
So, let's start with the case first.
00:18
So, the concept you can see that is we are going to use the enthalpy method for the calculations.
00:27
So, in the case first, we have asked for steam exist as saturated liquid.
00:37
As saturated liquid.
00:40
For this case, if you see from the question, the pressure first have been given that we say the initial pressure 100 kpa.
00:49
Now for steam table, we will get the final heat, we will say let's say h1.
00:57
So, that will be equals to from steam table that is 417 .51 kj per kg.
01:06
While if you look to the final volume that is let's say v1.
01:10
So it will be equals to 0 .001043 m3 per kg.
01:20
While the enthalpy is let's say f of f which will be equals to h1 which we will get from the table as 1 .3028 kj per kgk.
01:34
Now according to the state second, we are given the pressure v2 is 1 mpa which would be equals to 1000 kpa.
01:50
Right? while the enthalpy will be same as the initial one that is s1.
01:56
So, from steam table corresponding to these values of s2 and p2, we have the h2 would be equals to 418 .7 kj per kg.
02:13
And similarly, the volume second would be equals to 0 .00104 m3 per kg.
02:24
So, from here as we have to calculate the work input...