To get a peak load voltage of 40V out of a uncontrolled single phase bridge rectifier. What is the approximate rms value of secondary voltage? 14.4 V 56.6 V 0 V 28.3 V
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Step 1: The peak voltage of a single-phase bridge rectifier is related to the RMS voltage of the secondary by the following equation: $V_{peak} = \sqrt{2} V_{rms}$ Show more…
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The average value of a half-wave rectified voltage with a peak value of 200 V is (a) 63.7 V (b) 127.2 V (c) 141 V (d) 0 V. When a 60 Hz sinusoidal voltage is applied to the input of a half-wave rectifier, the output frequency is (a) 120 Hz (b) 30 Hz (c) 60 Hz (d) 0 Hz. The peak value of the input to a half-wave rectifier is 10 V. The approximate peak value of the output is (a) 10 V (b) 3.18 V (c) 10.7 V (d) 9.3 V. The average value of a full-wave rectified voltage with a peak value of 75 V is (a) 53 V (b) 47.8 V (c) 37.5 V (d) 23.9 V. When a 60 Hz sinusoidal voltage is applied to the input of a full-wave rectifier, the output frequency is (a) 120 Hz (b) 60 Hz (c) 240 Hz (d) 0 Hz. The total secondary voltage in a center-tapped full-wave rectifier is 125 V rms. Neglecting the diode drop, the rms output voltage is (a) 125 V (b) 177 V (c) 100 V (d) 62.5 V. When the peak output voltage is 100 V, the PIV for each diode in a center-tapped full-wave rectifier is (neglecting the diode drop) (a) 100 V (b) 200 V (c) 141 V (d) 50 V. When the rms output voltage of a bridge full-wave rectifier is 20 V, the peak inverse voltage across the diodes is (neglecting the diode drop) (a) 20 V (b) 40 V (c) 28.3 V (d) 56.6 V.
Adi S.
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