Training Bank Tellers A bank recently hired new tellers as...

Training Bank Tellers A bank recently hired new tellers as part of an expansion. These new tellers were put through a training program, and they are interested to see how prepared their new tellers are. To do this, they measure the time it took for them to complete transactions with customers. They analyzed 140 recent transactions of their 6 tellers. An incomplete ANOVA table of this analysis is provided below. DF SS MS F-stat p-val Groups A 3315 D F G Error B 58919 E Total C 62234 The first seven questions will have you fill out the values of this table based on the placeholder letters. When appropriate, give your answer rounded to 2 decimal places.

Transcript

00:01 Hello, let's have a look on the question.

00:01 So here, total observation are given to us, total observation is equal to 16, so n will be equal to 17, and total number of separate groups, total number of separate groups is equal to 3.

00:25 So we can say from here that p is equal to 3.

00:28 Now, to test null hypothesis and alternating hypothesis, h -0 null hypothesis is mu of a is equal to mu of b is equal to mu of c.

00:40 That means mean of all a, b, c are same.

00:44 And alternative is h0 is not true.

00:49 This is the alternative hypothesis.

00:51 Now we need to find out degree of freedom.

00:53 So degree of freedom is equal to n minus 1.

00:56 That is equal to 17 minus 1, that is 16.

00:59 Next, treatment of the treatment degree of freedom, treatment degree of freedom, is equal to p minus 1 that is equal to 3 minus 1 which is 2 so the value is equal to 2 now error degree of freedom error degree of freedom is equal to n minus p that is 17 minus 3 which is equal to 14 now we need to find out it is given to us that ss ss total is equal to 280 .9412 and ss treatment treatment is given to us which is equal to 156 .742.

01:54 This is given to us.

01:56 So from here we can find out the ss error.

02:00 So ss error will be equal to ss total minus ss treatment.

02:11 So this will be equal to 280 .9412 minus 156 point.

02:19 7412.

02:19 So this will be equal to 124 .2.

02:22 This is the value of ss error.

02:25 Now ms treatment ms treatment will be equal to ss treatment divided by degree of freedom treatment...

Question

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