00:01
In this question, we are given an argument which says dogs bark at cats, max is a dog, moon bean is a cat, therefore max barks at moonbeam.
00:40
This is the argument.
00:43
And we are also given predicates as b of x y, x, b b b of x, x backset, y, d of x as x is a dot, and c of x as x is a cat.
01:12
Now, we need to formalize this statement.
01:18
Now, this statement can be formalized as, firstly, for all x and for all y, d of x intersection c of y gives d of x, perma, y.
01:38
This is the renais...