A transverse wave on a string is modeled with the wave function y(x, t) = (0.80 m)sin[(0.35 m-1)x + (1.70 s-1)t + 0.20]. (Indicate the direction with the signs of your answers.) (a) Find the wave velocity (in m/s). 1.90 m/s (b) Find the position (in cm) in the y-direction, the velocity (in cm/s) perpendicular to the motion of the wave, and the acceleration (in cm/s2) perpendicular to the motion of the wave of a small segment of the string centered at x = 0.40 m at time t = 5.00 s. position cm velocity cm/s acceleration cm/s2
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80m * sin(0.35m^-1 * x + 1.70s^-1 * t + 0.20) Wave velocity formula: v = ω / k Given values: ω = 1.70 s^-1 k = 0.35 m^-1 Calculate the wave velocity: v = 1.70 s^-1 / 0.35 m^-1 v = 4.86 m/s ** Show more…
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