00:04
This question we're starting with our unbalanced equation.
00:08
We have nl3 minus, add s2 minus, produce n -o and s.
00:17
So we'll first have to balance this equation here.
00:20
Pyrr out major atoms, nitrogen, and sulfur.
00:25
So n -o -3 minus going to n -o.
00:30
Nitrogen's balance, so we need 2h -2o to balance the oxygen, three oxygen on each side, 4h plus to balance the hydrogen, three electrons to balance the charge, s2 minus going to s.
00:43
We need two electrons here to balance the electron charge, multiply by a common multiple for a number of electrons on each side.
00:54
This would give me six electrons, 8h plus, 2 on 03 minus, 2 and o, 4h2o, and minus 3s.
01:12
John's counsel.
01:13
Our balanced equation here becomes 2n03 minus 3s2 minus 8h plus 2n03s...