00:01
Hello students, here from the question, they given the data values of 3 treatments i .e.
00:08
Treatment 1, treatment 2 and then treatment 3.
00:15
The values are 3 .4, 1 .3, 4 .4, 5 .4 and then 2 .4, treatment 5 .5, 2 .7, 4 .6 and then 3 .2.
00:29
Then for treatment 3 which is 1 .4, 0 .7 and then 2 .1.
00:36
Here we need to frame a anova table for the given values.
00:42
That first we need to find the mean and standard deviation for the given data and the n values.
00:56
Here mean which is equal to 3 .38, the number of values which is equal to 5, the standard deviation 1 .61307.
01:08
Then for treatment 2, the mean value is 4 and the number of data values also 4, the standard deviation 1 .28323.
01:18
Then here the mean value which is 1 .4, the number of values 3, standard deviation is here 0 .7.
01:27
And the assumptions for anova, the randomness and independence, where samples are taken at random and are independent of each other.
01:55
Then we need to test the normality of the population...