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Hello students.
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This question is on trigonometric functions.
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Here we have sine curve in here this cosine curve.
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So we have sine 90 degree we can see it is equal to 1 here.
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We can write 1 cos 90 degree here.
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It is equal to 0 we can write 0 sine 0 degree.
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It is equal to 0 here.
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We have 0 while cos 0 degree we can see it is equal to 1 here.
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We will write 1 now.
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We are given a triangle here given triangle is a right angled triangle.
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So here we can make use of pythagoras theorem.
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So here we have hypotenuse square that is c.
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C square is equal to sum of side squares.
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So b square plus a square from here.
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We get c it is equal to under root b square plus a square.
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Now we have for 16 sine alpha.
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It is equal to perpendicular divided by hypotenuse.
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So here this is equal to we have perpendicular a divided by hypotenuse c.
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Next we have cos alpha.
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It is equal to base divided by hypotenuse.
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So here this is equal to we have here base b divided by hypotenuse c.
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We have number 18 tan alpha.
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It is equal to perpendicular divided by base here for alpha.
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We have perpendicular is a divided by base b.
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This is relation for number 19 here.
02:44
We have sine beta sine beta.
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It is equal to perpendicular divided by hypotenuse.
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So here we have sine beta.
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It is equal to for beta.
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We have perpendicular.
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It is equal to b to b by hypotenuse c.
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Next we have cos beta cos beta it is equal to base divided by hypotenuse here in this case.
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We have cos beta...