00:01
Hello student, to solve the given question, let us first calculate the time interval using the relation to h by g under root.
00:08
So here if we plug in the values for part a, we can calculate t equals 2 multiply by 1 .40 divided by 9 .8 under root.
00:20
So from here we get the final answer for part a, that is time interval is equal to 0 .53 seconds.
00:28
Similarly for the next case we can use the range relation that is range equals velocity here velocity is taken as v2 multiply by time t so from here if we plug in the values to find the velocity v2 it will be range divided by t and range is 7 .90 divided by t that is 0 .53 so from here we get the final answer for the speed v2 equals 14.
00:58
9 1 meters per second.
01:00
Now using the equation of continuity, that is a1 v1 equals a2 v2.
01:08
Further, this equation can be written as for part c, area can be written as pi r1 square, that is v1 equals pi r2 square v2.
01:24
From here pi will get cancelled and will get the value for v1, that is, r2 divided by r1 squared multiply by v2...