00:01
In this question, the steady load is given as p equals to 4 .5 kilo newton and the length of the tube is given as 750 mm.
00:10
Length equals to 750 mm.
00:15
The outer diameter of the tube is given as 18 mm and the inner diameter of the tube is given as 12 mm.
00:28
Now, we are going to calculate the stress.
00:30
The formula for calculating stress is p by a.
00:35
So, writing down the value, we know the value of p which is the load which is equal to 4500 divided by area.
00:44
Area is pi by 4 and squaring the diameter, inner and outer.
00:56
So now, by putting down the value, we will get the value of the stress which is equal to 31 .831 mpa.
01:05
We have calculated the stress.
01:07
Now, we are going to calculate deformation...