00:04
Steps of determining which reactant is limiting.
00:08
Evaluate, blah, blah, blah, blah.
00:10
So which of the following correctly describes the limiting reactant? calculate the theoretical yield of co.
00:21
So here is, is that co2 or co2? it looks like it's methane.
00:29
I'm guessing i'm given methane here.
00:31
I can't read this.
00:36
Plus 202, yeah, it must be methane.
00:38
And that will produce co2 and two waters.
00:46
I'm guessing that this is my equation.
00:49
And i'm told i have 29 .3 grams of methane.
00:57
I need to find my theoretical yield in moles of co2.
01:25
Okay? which of the following correctly describes a limiting reactant? and there's nothing there for that question.
01:35
Let's see if i can find if anybody else is putting.
01:38
Anything anywhere with more information about this.
01:42
It's a poorly loaded question.
01:50
Evaluate the question, which of the following correctly describes.
02:09
Okay, and then somewhere it says which of the following describes the limiting reactant, but we're not given anything.
02:14
So i'm just going to go ahead and do my theoretical yield from 29 .3 grams of ch4.
02:24
My students report their molar masses to two decimal places, so they would use 16 .05 grams of ch4 per mole of ch4.
02:38
I have a one -to -one mole ratio for co2 and ch4, and this will give me 29 .3 divided by 16 .05.
02:54
That will be reported to three significant figures, 1 .83 moles of co2.
03:07
Calculate the theoretical yielded moles of co2 if i have 81 .7 grams of o.
03:21
So now i'm doing the same thing, but i have 81 .7 grams of o2, and i'm also finding the theoretical yield of co2.
03:43
This is 32 .00 grams of o2 per mole of o2, and then i'll multiply that, by my mole ratio of 1 mole of co2 for 2 moles of 02.
03:59
This will equal 81 .7 divided by 32 divided by 2.
04:06
And this is 1 .28 moles of co2.
04:12
That is my second question.
04:14
So this is my first question...