Question

Tutorial: Electric Fields 1 F. You should have found the electric field in C to be twice as strong as the electric field in D. But the electric forces that the two beads feel are the same. How can this be? G. The charge on bead 1 is now tripled. How does that affect: 1. the magnitude of the force felt by bead 1? Explain. 2. the magnitude of the force felt by bead 2? Explain. 3. the strength of the electric field caused by bead 2 at the location occupied by bead 1? Explain. 4. the strength of the electric field caused by bead 1 at the location occupied by bead 2? Explain. H. We will now consider a point P at some distance to the right of bead 2. This is just a point for now, there is no charge placed there. What is the direction of the electric field at point P? Hint: Both bead 1 and bead 2 create electric fields at point P. What are the directions of these electric fields? 1 2 P I. A 2.5 C charge is placed at point P. What is the direction of the electric force it feels? J. If the force acting on the 2.5 C charge is 20 N, what is the magnitude of the electric field at point P (caused by beads 1 and 2)? K. The 2.5 C charge at P is replaced by a 5.0 C charge. Find. 1. the overall electric field (magnitude and direction) caused by both beads 1 and 2 at P when the 5.0 C charge is present. 2. the electric force on that 5.0 C charge. Consult your group partners before you proceed. If possible, consult an instructor.

          Tutorial: Electric Fields 1
F. You should have found the electric field in C to be twice as strong as the electric field in D. But the electric forces that the two beads feel are the same. How can this be?
G. The charge on bead 1 is now tripled. How does that affect:
1. the magnitude of the force felt by bead 1? Explain.
2. the magnitude of the force felt by bead 2? Explain.
3. the strength of the electric field caused by bead 2 at the location occupied by bead 1? Explain.
4. the strength of the electric field caused by bead 1 at the location occupied by bead 2? Explain.
H. We will now consider a point P at some distance to the right of bead 2. This is just a point for now, there is no charge placed there. What is the direction of the electric field at point P?
Hint: Both bead 1 and bead 2 create electric fields at point P. What are the directions of these electric fields?
1
2
P
I. A 2.5 C charge is placed at point P. What is the direction of the electric force it feels?
J. If the force acting on the 2.5 C charge is 20 N, what is the magnitude of the electric field at point P (caused by beads 1 and 2)?
K. The 2.5 C charge at P is replaced by a 5.0 C charge. Find.
1. the overall electric field (magnitude and direction) caused by both beads 1 and 2 at P when the 5.0 C charge is present.
2. the electric force on that 5.0 C charge.
Consult your group partners before you proceed. If possible, consult an instructor.

Tutorial: Electric Fields 1
F. You should have found the electric field in C to be twice as strong as the electric field in D. But the electric forces that the two beads feel are the same. How can this be?
G. The charge on bead 1 is now tripled. How does that affect:
1. the magnitude of the force felt by bead 1? Explain.
2. the magnitude of the force felt by bead 2? Explain.
3. the strength of the electric field caused by bead 2 at the location occupied by bead 1? Explain.
4. the strength of the electric field caused by bead 1 at the location occupied by bead 2? Explain.
H. We will now consider a point P at some distance to the right of bead 2. This is just a point for now, there is no charge placed there. What is the direction of the electric field at point P?
Hint: Both bead 1 and bead 2 create electric fields at point P. What are the directions of these electric fields?
1
2
P
I. A 2.5 C charge is placed at point P. What is the direction of the electric force it feels?
J. If the force acting on the 2.5 C charge is 20 N, what is the magnitude of the electric field at point P (caused by beads 1 and 2)?
K. The 2.5 C charge at P is replaced by a 5.0 C charge. Find.
1. the overall electric field (magnitude and direction) caused by both beads 1 and 2 at P when the 5.0 C charge is present.
2. the electric force on that 5.0 C charge.
Consult your group partners before you proceed. If possible, consult an instructor.

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