00:01
This question, the equivalent resistance of two resistors in series is 50 om and 20 om.
00:10
If they are connected in parallel, then what is the resistance of the two resistors? so the equivalent resistance of two resistors in the series is, so it is given to us that when they are connected in series, let's r1 and r2 be the individual resistances, it is 50 om when they are connected in series.
00:30
And when they are connected in parallel that is 12 oms so in parallel the equivalent resistance is r1 r2 over r1 plus r2 this is given as 12 and r1 plus r2 is already 50 so r1 r2 is given to us as over 50 is nothing but 12 and if we cross multiply then r1 r2 is 12 times 5 is 60 which is 600 this is equation 1 this is equation 2 so from first and second we can solve for r1 and r2 so from first the value of r1 is coming as 50 minus r2.
01:05
So from second, the value of r1 is replaced by 50 minus r2 and r2 remains as it is equal to 600.
01:17
So this becomes 50 r2 minus r2 square is 600.
01:26
And let's continue over here.
01:28
This would mean that r2 square minus 50 r2 plus 600 is equal to zero.
01:36
Now let's see, can we factorize this 60 times 10? yes, i think we can...