Two 2.30 cmcm ×× 2.30 cmcm plates that form a parallel-plate capacitor are charged to ±± 0.708 nCnC . What is the electric field strength inside the capacitor if the spacing between the plates is 1.20 mmmm ?
Added by Robert R.
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The area \( A \) of each plate can be calculated using the formula for the area of a square: \[ A = \text{side}^2 = (2.30 \, \text{cm})^2 = (0.0230 \, \text{m})^2 = 0.000529 \, \text{m}^2 \] Show more…
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