Two aluminum pieces are bonded to a steel bar. A moment of 100 kip.in about the x-axis is applied to the section shown. Determine the maximum stress in the aluminum and steel bar, $E_s = 29 \times 10^6$ psi and $E_a = 10.6 \times 10^6$ psi.
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The moment of inertia for a rectangular section is given by the formula: I = (1/12) * b * h^3 For the aluminum section, the width (b) is 2 inches and the height (h) is 2 inches. Therefore, the moment of inertia for the aluminum section is: I_al = (1/12) * 2 * Show more…
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